2[3(x-7)+7]=6x-28

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Solution for 2[3(x-7)+7]=6x-28 equation:


Simplifying
2[3(x + -7) + 7] = 6x + -28

Reorder the terms:
2[3(-7 + x) + 7] = 6x + -28
2[(-7 * 3 + x * 3) + 7] = 6x + -28
2[(-21 + 3x) + 7] = 6x + -28

Reorder the terms:
2[-21 + 7 + 3x] = 6x + -28

Combine like terms: -21 + 7 = -14
2[-14 + 3x] = 6x + -28
[-14 * 2 + 3x * 2] = 6x + -28
[-28 + 6x] = 6x + -28

Reorder the terms:
-28 + 6x = -28 + 6x

Add '28' to each side of the equation.
-28 + 28 + 6x = -28 + 28 + 6x

Combine like terms: -28 + 28 = 0
0 + 6x = -28 + 28 + 6x
6x = -28 + 28 + 6x

Combine like terms: -28 + 28 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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